The solution to -3\div 2+1 is -1/2

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-3\div 2+1

Solution

- 3 \div 2 + 1

- \frac{1}{2}

Solution steps

- 3 \div 2 + 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

- 3 \div 2 : \frac{- 3}{2}

- 3 \div 2

- 3 \div 2 = \frac{- 3}{2}

= \frac{- 3}{2}

= \frac{- 3}{2} + 1

Add and subtract (left to right)

\frac{- 3}{2} + 1 : - \frac{1}{2}

\frac{- 3}{2} + 1

\frac{- 3}{2} + 1 = - \frac{1}{2}

\frac{- 3}{2} + 1

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{2} + 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} - \frac{3}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 - 3}{2}

1 \cdot 2 - 3 = - 1

1 \cdot 2 - 3

Multiply the numbers:

1 \cdot 2 = 2

= 2 - 3

Subtract the numbers:

2 - 3 = - 1

= - 1

= \frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

= - \frac{1}{2}

= - \frac{1}{2}

4 - 6 \times 2 \div 2 + 2

+ 7 - 8 - 5 + 9 - 6 + 5 + 16 + 20 - 10 - 4

2 (4) - 2

2 (4) - 7

236 + 417 - 144 + 14 \cdot 2 - 36 \div 9