What is 3(-3)^2+6(-3)-9 ?

The solution to 3(-3)^2+6(-3)-9 is 0

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3(-3)^2+6(-3)-9

3 (- 3)^{2} + 6 (- 3) - 9

0

Solution steps

3 (- 3)^{2} + 6 (- 3) - 9

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 3 \cdot 9 + 6 (- 3) - 9

Multiply and divide (left to right)

3 \cdot 9 : 27

3 \cdot 9

3 \cdot 9 = 27

= 27

= 27 + 6 (- 3) - 9

Multiply and divide (left to right)

6 (- 3) : - 18

6 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 3) = - 6 \cdot 3 = - 18

= - 18

= 27 - 18 - 9

Add and subtract (left to right)

27 - 18 - 9 : 0

27 - 18 - 9

27 - 18 = 9

= 9 - 9

9 - 9 = 0

= 0

= 0

12 + 8^{2} + 3^{2}

(2 + 5 \times (2 + 3) + 5) \times 2

4 (2) - 4 (- 2)

\frac{4 ( 2 ) ^{3}}{3}

(12 - 5)^{2}