What is ((-5)^2-3(7))/((-2)^2-(9-3)) ?

The solution to ((-5)^2-3(7))/((-2)^2-(9-3)) is -2

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((-5)^2-3(7))/((-2)^2-(9-3))

\frac{( - 5 ) ^{2} - 3 ( 7 )}{( - 2 ) ^{2} - ( 9 - 3 )}

- 2

Solution steps

\frac{( - 5 ) ^{2} - 3 ( 7 )}{( - 2 ) ^{2} - ( 9 - 3 )}

Solve

(- 5)^{2} - 3 (7) : 4

Follow the PEMDAS order of operations

Calculate exponents

(- 5)^{2} : 25

(- 5)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2} = 25

= 25

= 25 - 3 (7)

Multiply and divide (left to right)

3 (7) : 21

3 (7)

Apply rule:

(a) = a

(7) = 7

= 3 \cdot 7

Multiply the numbers:

3 \cdot 7 = 21

= 21

= 25 - 21

Add and subtract (left to right)

25 - 21 : 4

25 - 21

25 - 21 = 4

= 4

= 4

Solve

(- 2)^{2} - (9 - 3) : - 2

Follow the PEMDAS order of operations

Calculate within parentheses

(9 - 3) : 6

9 - 3

9 - 3 = 6

= 6

= (- 2)^{2} - 6

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 - 6

Add and subtract (left to right)

4 - 6 : - 2

4 - 6

4 - 6 = - 2

= - 2

= - 2

= \frac{4}{- 2}

Simplify

\frac{4}{- 2} : - 2

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= - 2

= - 2

128 \div 2 \div 2 \div 8

- 5 (\frac{1}{3} + 2) + 6

4 (1)^{3} - 12 (1)^{2}

4^{2} \cdot 2

81 \div 3 \times 50

What is ((-5)^2-3(7))/((-2)^2-(9-3)) ?
The solution to ((-5)^2-3(7))/((-2)^2-(9-3)) is -2