What is 10\times 5-(-6)^2+(-8) ?

The solution to 10\times 5-(-6)^2+(-8) is 6

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10\times 5-(-6)^2+(-8)

10 \cdot 5 - (- 6)^{2} + (- 8)

6

Solution steps

10 \cdot 5 - (- 6)^{2} + (- 8)

Follow the PEMDAS order of operations

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= 10 \cdot 5 - 36 + (- 8)

Multiply and divide (left to right)

10 \cdot 5 : 50

10 \cdot 5

10 \cdot 5 = 50

= 50

= 50 - 36 + (- 8)

Add and subtract (left to right)

50 - 36 + (- 8) : 6

50 - 36 + (- 8)

50 - 36 = 14

= 14 + (- 8)

Apply rule

+ (- a) = - a

+ (- 8) = - 8

= 14 - 8

14 - 8 = 6

= 6

= 6

3 [2 - 4 (7 - 12)]

\frac{63}{5} \times (1 - \frac{6}{7})

90 + (70% \times 90)

- 2 \cdot (- \frac{3}{2}) + 2

\frac{5}{- 1 ^{2} + 4}