What is (-2)^{100}+(-16)^{25} ?

The solution to (-2)^{100}+(-16)^{25} is 0

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(-2)^{100}+(-16)^{25}

(- 2)^{100} + (- 16)^{25}

0

Solution steps

(- 2)^{100} + (- 16)^{25}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{100} : 1.26765 E 30

(- 2)^{100}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{100} = 2^{100} = 1.26765 E 30

= 1.26765 E 30

= 1.26765 E 30 + (- 16)^{25}

Calculate exponents

(- 16)^{25} : - 1.26765 E 30

(- 16)^{25}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 16)^{25} = - 1 6^{25} = - 1.26765 E 30

= - 1.26765 E 30

= 1.26765 E 30 - 1.26765 E 30

Add and subtract (left to right)

1.26765 E 30 - 1.26765 E 30 : 0

1.26765 E 30 - 1.26765 E 30

1.26765 E 30 - 1.26765 E 30 = 0

= 0

= 0

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