What is (3/2+2)*(2-12/7) ?

The solution to (3/2+2)*(2-12/7) is 1

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(3/2+2)*(2-12/7)

(\frac{3}{2} + 2) \cdot (2 - \frac{12}{7})

1

Solution steps

(\frac{3}{2} + 2) (2 - \frac{12}{7})

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{3}{2} + 2) : \frac{7}{2}

\frac{3}{2} + 2

\frac{3}{2} + 2 = \frac{7}{2}

\frac{3}{2} + 2

Convert element to fraction:

2 = \frac{2 \cdot 2}{2}

= \frac{2 \cdot 2}{2} + \frac{3}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 2 + 3}{2}

2 \cdot 2 + 3 = 7

2 \cdot 2 + 3

Multiply the numbers:

2 \cdot 2 = 4

= 4 + 3

Add the numbers:

4 + 3 = 7

= 7

= \frac{7}{2}

= \frac{7}{2}

= \frac{7}{2} (2 - \frac{12}{7})

Calculate within parentheses

(2 - \frac{12}{7}) : \frac{2}{7}

2 - \frac{12}{7}

2 - \frac{12}{7} = \frac{2}{7}

2 - \frac{12}{7}

Convert element to fraction:

2 = \frac{2 \cdot 7}{7}

= \frac{2 \cdot 7}{7} - \frac{12}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 7 - 12}{7}

2 \cdot 7 - 12 = 2

2 \cdot 7 - 12

Multiply the numbers:

2 \cdot 7 = 14

= 14 - 12

Subtract the numbers:

14 - 12 = 2

= 2

= \frac{2}{7}

= \frac{2}{7}

= \frac{7}{2} \cdot \frac{2}{7}

Multiply and divide (left to right)

\frac{7}{2} \cdot \frac{2}{7} : 1

\frac{7}{2} \cdot \frac{2}{7}

\frac{7}{2} \cdot \frac{2}{7} = 1

= 1

= 1

5 - 2 - (- 3) - 6

5 + 10 \div 5 \times 2

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2^{2} \times \frac{1}{2} \times \frac{1}{3}