What is (2-3/4)-(1-1/4) ?

The solution to (2-3/4)-(1-1/4) is 1/2

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(2-3/4)-(1-1/4)

(2 - \frac{3}{4}) - (1 - \frac{1}{4})

\frac{1}{2}

Solution steps

(2 - \frac{3}{4}) - (1 - \frac{1}{4})

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - \frac{3}{4}) : \frac{5}{4}

2 - \frac{3}{4}

2 - \frac{3}{4} = \frac{5}{4}

2 - \frac{3}{4}

Convert element to fraction:

2 = \frac{2 \cdot 4}{4}

= \frac{2 \cdot 4}{4} - \frac{3}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 4 - 3}{4}

2 \cdot 4 - 3 = 5

2 \cdot 4 - 3

Multiply the numbers:

2 \cdot 4 = 8

= 8 - 3

Subtract the numbers:

8 - 3 = 5

= 5

= \frac{5}{4}

= \frac{5}{4}

= \frac{5}{4} - (1 - \frac{1}{4})

Calculate within parentheses

(1 - \frac{1}{4}) : \frac{3}{4}

1 - \frac{1}{4}

1 - \frac{1}{4} = \frac{3}{4}

1 - \frac{1}{4}

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} - \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 - 1}{4}

1 \cdot 4 - 1 = 3

1 \cdot 4 - 1

Multiply the numbers:

1 \cdot 4 = 4

= 4 - 1

Subtract the numbers:

4 - 1 = 3

= 3

= \frac{3}{4}

= \frac{3}{4}

= \frac{5}{4} - \frac{3}{4}

Add and subtract (left to right)

\frac{5}{4} - \frac{3}{4} : \frac{1}{2}

\frac{5}{4} - \frac{3}{4}

\frac{5}{4} - \frac{3}{4} = \frac{1}{2}

\frac{5}{4} - \frac{3}{4}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 - 3}{4}

Subtract the numbers:

5 - 3 = 2

= \frac{2}{4}

Cancel the common factor:

2

= \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

- \frac{1}{4} (- 5)^{2} + 4

\frac{180 ( 5 - 2 )}{5}

- 12 + 7 - 9 \cdot 3

6 (- 4)^{2}

5 - (- 2) + (- 8) \div (- 4) - 5