The solution to 1-1/4-1/4 is 1/2

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1-1/4-1/4

Solution

1 - \frac{1}{4} - \frac{1}{4}

\frac{1}{2}

Solution steps

1 - \frac{1}{4} - \frac{1}{4}

Follow the PEMDAS order of operations

Add and subtract (left to right)

1 - \frac{1}{4} = \frac{3}{4}

1 - \frac{1}{4}

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} - \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 - 1}{4}

1 \cdot 4 - 1 = 3

1 \cdot 4 - 1

Multiply the numbers:

1 \cdot 4 = 4

= 4 - 1

Subtract the numbers:

4 - 1 = 3

= 3

= \frac{3}{4}

= \frac{3}{4} - \frac{1}{4}

\frac{3}{4} - \frac{1}{4} = \frac{1}{2}

\frac{3}{4} - \frac{1}{4}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 - 1}{4}

Subtract the numbers:

3 - 1 = 2

= \frac{2}{4}

Cancel the common factor:

2

= \frac{1}{2}

= \frac{1}{2}

\frac{7 ^{2} - 5 ^{2}}{- 4}

5 - 3 (2 - 12) + 8 (11 - 14)

(- 4)^{2} - (- 1)^{4}

- 7 [9 - 2 (3 + 1)] + 5

4 \times 5 - 3