What is [(-3)(-4)+(-1)(+2)-(1)(-2)]\div (+2)(-2) ?

The solution to [(-3)(-4)+(-1)(+2)-(1)(-2)]\div (+2)(-2) is -12

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[(-3)(-4)+(-1)(+2)-(1)(-2)]\div (+2)(-2)

[(- 3) (- 4) + (- 1) (+ 2) - (1) (- 2)] \div (+ 2) (- 2)

- 12

Solution steps

[(- 3) (- 4) + (- 1) (2) - (1) (- 2)] \div (2) (- 2)

Follow the PEMDAS order of operations

Calculate within parentheses

[(- 3) (- 4) + (- 1) (2) - (1) (- 2)] : 12

(- 3) (- 4) + (- 1) (2) - (1) (- 2)

Multiply and divide (left to right)

(- 3) (- 4) : 12

(- 3) (- 4)

Apply rule

(- a) \cdot (- b) = a \cdot b

(- 3) (- 4) = 3 \cdot 4 = 12

= 12

= 12 + (- 1) (2) - (1) (- 2)

Multiply and divide (left to right)

(- 1) (2) : - 2

(- 1) (2)

Apply rule

(- a) \cdot (b) = - a \cdot b

(- 1) (2) = - 1 \cdot 2 = - 2

= - 2

= 12 - 2 - (1) (- 2)

Multiply and divide (left to right)

(1) (- 2) : - 2

(1) (- 2)

Apply rule

(a) \cdot (- b) = - a \cdot b

(1) (- 2) = - 1 \cdot 2 = - 2

= - 2

= 12 - 2 - (- 2)

Add and subtract (left to right)

12 - 2 - (- 2) : 12

12 - 2 - (- 2)

12 - 2 = 10

= 10 - (- 2)

Apply rule

- (- a) = + a

- (- 2) = + 2

= 10 + 2

10 + 2 = 12

= 12

= 12

= 12 \div (2) (- 2)

Multiply and divide (left to right)

12 \div (2) (- 2) : - 12

12 \div (2) (- 2)

12 \div (2) = \frac{12}{( 2 )}

= \frac{12}{( 2 )} (- 2)

\frac{12}{( 2 )} (- 2) = - 12

\frac{12}{( 2 )} (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{12}{( 2 )} (- 2) = - \frac{12}{( 2 )} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= - \frac{12}{2} \cdot \frac{2}{1}

Cross-cancel common factor:

2

= - \frac{12}{1}

Divide the numbers:

\frac{12}{1} = 12

= - 12

= - 12

= - 12

(6 + 4)^{2}

3 \cdot (2 + 3 - 4) - 40 \div 20

3 \cdot 9 + 6^{2}

- 2 (- 1) + 1

1 - \frac{1}{3} \times \frac{1}{4}

What is [(-3)(-4)+(-1)(+2)-(1)(-2)]\div (+2)(-2) ?
The solution to [(-3)(-4)+(-1)(+2)-(1)(-2)]\div (+2)(-2) is -12