What is (-4)^4-15(-4)^2+10(-4)+24 ?

The solution to (-4)^4-15(-4)^2+10(-4)+24 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(-4)^4-15(-4)^2+10(-4)+24

(- 4)^{4} - 15 (- 4)^{2} + 10 (- 4) + 24

0

Solution steps

(- 4)^{4} - 15 (- 4)^{2} + 10 (- 4) + 24

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{4} : 256

(- 4)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{4} = 4^{4} = 256

= 256

= 256 - 15 (- 4)^{2} + 10 (- 4) + 24

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 256 - 15 \cdot 16 + 10 (- 4) + 24

Multiply and divide (left to right)

15 \cdot 16 : 240

15 \cdot 16

15 \cdot 16 = 240

= 240

= 256 - 240 + 10 (- 4) + 24

Multiply and divide (left to right)

10 (- 4) : - 40

10 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

10 (- 4) = - 10 \cdot 4 = - 40

= - 40

= 256 - 240 - 40 + 24

Add and subtract (left to right)

256 - 240 - 40 + 24 : 0

256 - 240 - 40 + 24

256 - 240 = 16

= 16 - 40 + 24

16 - 40 = - 24

= - 24 + 24

- 24 + 24 = 0

= 0

= 0

16 (- 3) - (- 3)^{5}

15 \div 5 - 2

3 - 3 \frac{5}{8} \div 1 \frac{5}{24}

(3 \cdot 5)^{6}

(30 + 4) \div (5 \times 4 - 3) + (10 + 4) \div (6 + 8)

What is (-4)^4-15(-4)^2+10(-4)+24 ?
The solution to (-4)^4-15(-4)^2+10(-4)+24 is 0