The solution to (2+2)^2-4 is 12

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(2+2)^2-4

Solution

(2 + 2)^{2} - 4

12

Solution steps

(2 + 2)^{2} - 4

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 2) : 4

2 + 2

2 + 2 = 4

= 4

= 4^{2} - 4

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 - 4

Add and subtract (left to right)

16 - 4 : 12

16 - 4

16 - 4 = 12

= 12

= 12

- (- 8)^{2} - 6 (- 8) + 7

(6) - (7) + (- 7) - (- 6) - (2)

5 + (42 \div 7) + 18 - (4 \times 2) + 46

\frac{1}{9} \times 15 + 5 \div 3

45 - (- 32) + (- 12) - (- 7)