What is 1/4 (2^3+4^2) ?

The solution to 1/4 (2^3+4^2) is 6

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1/4 (2^3+4^2)

\frac{1}{4} (2^{3} + 4^{2})

6

Solution steps

\frac{1}{4} (2^{3} + 4^{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(2^{3} + 4^{2}) : 24

2^{3} + 4^{2}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 + 4^{2}

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 8 + 16

Add and subtract (left to right)

8 + 16 : 24

8 + 16

8 + 16 = 24

= 24

= 24

= \frac{1}{4} \cdot 24

Multiply and divide (left to right)

\frac{1}{4} \cdot 24 : 6

\frac{1}{4} \cdot 24

Convert element to fraction:

24 = \frac{24}{1}

= \frac{1}{4} \cdot \frac{24}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 24}{4 \cdot 1}

\frac{1 \cdot 24}{4 \cdot 1} = 6

\frac{1 \cdot 24}{4 \cdot 1}

\frac{1 \cdot 24}{4 \cdot 1} = \frac{24}{4}

\frac{1 \cdot 24}{4 \cdot 1}

Multiply the numbers:

1 \cdot 24 = 24

= \frac{24}{4 \cdot 1}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{24}{4}

= \frac{24}{4}

Divide the numbers:

\frac{24}{4} = 6

= 6

= 6

= 6

18 - \frac{36}{4} \times \frac{12}{- 3}

2^{2} - 4 (2) + 5

5^{0} + 4^{0}

5^{0} - 7^{0} - (- 8^{0})^{0} - 9 (- 6^{0})

2 \cdot \frac{1}{10} - 1