What is (-2+1)/(-2^2+(-2)) ?

The solution to (-2+1)/(-2^2+(-2)) is 1/6

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(-2+1)/(-2^2+(-2))

\frac{- 2 + 1}{- 2 ^{2} + ( - 2 )}

\frac{1}{6}

Solution steps

\frac{- 2 + 1}{- 2 ^{2} + ( - 2 )}

Solve

- 2 + 1 : - 1

- 2 + 1 = - 1

= - 1

Solve

- 2^{2} + (- 2) : - 6

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= - 4 + (- 2)

Add and subtract (left to right)

- 4 + (- 2) : - 6

- 4 + (- 2)

Apply rule

+ (- a) = - a

+ (- 2) = - 2

= - 4 - 2

- 4 - 2 = - 6

= - 6

= - 6

= \frac{- 1}{- 6}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{1}{6}

- 4 + (- 3 + (- 5 + 9 - 2))

2 \cdot 3 + 6/2

17 - 5 \cdot 4 \div 2

4 + 5^{2} - (- 3)^{3} + 6

2 \div \frac{8}{5} - \frac{16}{3} \div 4