What is 7^2+3(4^2+3+2) ?

The solution to 7^2+3(4^2+3+2) is 112

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7^2+3(4^2+3+2)

7^{2} + 3 (4^{2} + 3 + 2)

112

Solution steps

7^{2} + 3 (4^{2} + 3 + 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(4^{2} + 3 + 2) : 21

4^{2} + 3 + 2

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 + 3 + 2

Add and subtract (left to right)

16 + 3 + 2 : 21

16 + 3 + 2

16 + 3 = 19

= 19 + 2

19 + 2 = 21

= 21

= 21

= 7^{2} + 3 \cdot 21

Calculate exponents

7^{2} : 49

7^{2}

7^{2} = 49

= 49

= 49 + 3 \cdot 21

Multiply and divide (left to right)

3 \cdot 21 : 63

3 \cdot 21

3 \cdot 21 = 63

= 63

= 49 + 63

Add and subtract (left to right)

49 + 63 : 112

49 + 63

49 + 63 = 112

= 112

= 112

\frac{11}{15}

1 2^{2} + 1 5^{2}

\frac{360}{2}

0.5 \cdot 0.5

\frac{135}{5}