What is -2^3\div 3^2 ?

The solution to -2^3\div 3^2 is -8/9

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-2^3\div 3^2

- 2^{3} \div 3^{2}

- \frac{8}{9}

Solution steps

- 2^{3} \div 3^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= - 8 \div 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 8 \div 9

Multiply and divide (left to right)

- 8 \div 9 : \frac{- 8}{9}

- 8 \div 9

- 8 \div 9 = \frac{- 8}{9}

= \frac{- 8}{9}

= \frac{- 8}{9}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8}{9}

- 6^{2} + 5 \cdot (- 6) - 1

[(- 5) \cdot (- 2) - (- 4) \cdot (- 3)]^{3}

2 \times (7 + 1) - 32 \div (7 + 9)

5 (- 2) - 3

2 (- 2)^{2} + 1