What is (7)\div 5\div (6-9/2) ?

The solution to (7)\div 5\div (6-9/2) is 14/15

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(7)\div 5\div (6-9/2)

(7) \div 5 \div (6 - \frac{9}{2})

\frac{14}{15}

Solution steps

(7) \div 5 \div (6 - \frac{9}{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(6 - \frac{9}{2}) : \frac{3}{2}

6 - \frac{9}{2}

6 - \frac{9}{2} = \frac{3}{2}

6 - \frac{9}{2}

Convert element to fraction:

6 = \frac{6 \cdot 2}{2}

= \frac{6 \cdot 2}{2} - \frac{9}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{6 \cdot 2 - 9}{2}

6 \cdot 2 - 9 = 3

6 \cdot 2 - 9

Multiply the numbers:

6 \cdot 2 = 12

= 12 - 9

Subtract the numbers:

12 - 9 = 3

= 3

= \frac{3}{2}

= \frac{3}{2}

= (7) \div 5 \div \frac{3}{2}

Multiply and divide (left to right)

(7) \div 5 \div \frac{3}{2} : \frac{14}{15}

(7) \div 5 \div \frac{3}{2}

(7) \div 5 = \frac{( 7 )}{5}

= \frac{( 7 )}{5} \div \frac{3}{2}

\frac{( 7 )}{5} \div \frac{3}{2} = \frac{14}{15}

\frac{( 7 )}{5} \div \frac{3}{2}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{( 7 )}{5} \cdot \frac{2}{3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{7 \cdot 2}{5 \cdot 3}

Multiply the numbers:

7 \cdot 2 = 14

= \frac{14}{5 \cdot 3}

Multiply the numbers:

5 \cdot 3 = 15

= \frac{14}{15}

= \frac{14}{15}

= \frac{14}{15}

(- 8) + (+ 1) + (- 4) + (+ 1)

4 \cdot 3^{3}

3 (3)^{2} + 5

6 - (4 - 3 (4 - 2)) - (7 - 5 (4 - 2 (7 - 1)))

2 4^{2} + 2 5^{2}