What is 2(-1)^2+4(-1) ?

The solution to 2(-1)^2+4(-1) is -2

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2(-1)^2+4(-1)

2 (- 1)^{2} + 4 (- 1)

- 2

Solution steps

2 (- 1)^{2} + 4 (- 1)

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 2 \cdot 1 + 4 (- 1)

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 2 + 4 (- 1)

Multiply and divide (left to right)

4 (- 1) : - 4

4 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 1) = - 4 \cdot 1 = - 4

= - 4

= 2 - 4

Add and subtract (left to right)

2 - 4 : - 2

2 - 4

2 - 4 = - 2

= - 2

= - 2

2 + 5 (8 - 5)

4^{2} \cdot 3^{2}

(4 \cdot 3)^{2}

4 - (- 3)^{2}

- 2 (2)^{2} + 4 (2) + 1