What is (1)^3-2(1)^2+3(1)+5 ?

The solution to (1)^3-2(1)^2+3(1)+5 is 7

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(1)^3-2(1)^2+3(1)+5

(1)^{3} - 2 (1)^{2} + 3 (1) + 5

7

Solution steps

(1)^{3} - 2 (1)^{2} + 3 (1) + 5

Follow the PEMDAS order of operations

Calculate exponents

(1)^{3} : 1

(1)^{3}

(1)^{3} = 1

= 1

= 1 - 2 (1)^{2} + 3 (1) + 5

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 1 - 2 \cdot 1 + 3 (1) + 5

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 1 - 2 + 3 (1) + 5

Multiply and divide (left to right)

3 (1) : 3

3 (1)

Apply rule:

(a) = a

(1) = 1

= 3 \cdot 1

Multiply the numbers:

3 \cdot 1 = 3

= 3

= 1 - 2 + 3 + 5

Add and subtract (left to right)

1 - 2 + 3 + 5 : 7

1 - 2 + 3 + 5

1 - 2 = - 1

= - 1 + 3 + 5

- 1 + 3 = 2

= 2 + 5

2 + 5 = 7

= 7

= 7

- (- 24) + (- 13) - (9)

(- 9 + 6) \times (- 2 - 5)

- 2^{3} - 1

3 (2 + 5)

4 \times 3 \div 6