What is (7-5)(3-2-4\div 2-3(6-2-8\div 4)) ?

The solution to (7-5)(3-2-4\div 2-3(6-2-8\div 4)) is -14

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(7-5)(3-2-4\div 2-3(6-2-8\div 4))

(7 - 5) (3 - 2 - 4 \div 2 - 3 (6 - 2 - 8 \div 4))

- 14

Solution steps

(7 - 5) (3 - 2 - 4 \div 2 - 3 (6 - 2 - 8 \div 4))

Follow the PEMDAS order of operations

Calculate within parentheses

(7 - 5) : 2

7 - 5

7 - 5 = 2

= 2

= 2 (3 - 2 - 4 \div 2 - 3 (6 - 2 - 8 \div 4))

Calculate within parentheses

(3 - 2 - 4 \div 2 - 3 (6 - 2 - 8 \div 4)) : - 7

3 - 2 - 4 \div 2 - 3 (6 - 2 - 8 \div 4)

Calculate within parentheses

(6 - 2 - 8 \div 4) : 2

6 - 2 - 8 \div 4

Multiply and divide (left to right)

8 \div 4 : 2

8 \div 4

8 \div 4 = 2

= 2

= 6 - 2 - 2

Add and subtract (left to right)

6 - 2 - 2 : 2

6 - 2 - 2

6 - 2 = 4

= 4 - 2

4 - 2 = 2

= 2

= 2

= 3 - 2 - 4 \div 2 - 3 \cdot 2

Multiply and divide (left to right)

4 \div 2 : 2

4 \div 2

4 \div 2 = 2

= 2

= 3 - 2 - 2 - 3 \cdot 2

Multiply and divide (left to right)

3 \cdot 2 : 6

3 \cdot 2

3 \cdot 2 = 6

= 6

= 3 - 2 - 2 - 6

Add and subtract (left to right)

3 - 2 - 2 - 6 : - 7

3 - 2 - 2 - 6

3 - 2 = 1

= 1 - 2 - 6

1 - 2 = - 1

= - 1 - 6

- 1 - 6 = - 7

= - 7

= - 7

= 2 (- 7)

Multiply and divide (left to right)

2 (- 7) : - 14

2 (- 7)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 7) = - 2 \cdot 7 = - 14

= - 14

= - 14

1 7^{2} - 64

578 - 245 + 5 + 34 \times 3

5 \times 2^{3} - (- 2)^{5} - (- 2)^{2} + (- 1)^{7}

81 \div 9 - (3 \times 4 \times 5) + 64 - 32 \div 4

4 \times (- 2) - 5

What is (7-5)(3-2-4\div 2-3(6-2-8\div 4)) ?
The solution to (7-5)(3-2-4\div 2-3(6-2-8\div 4)) is -14