What is 2/(4(-2)^2+1) ?

The solution to 2/(4(-2)^2+1) is 2/17

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2/(4(-2)^2+1)

\frac{2}{4 ( - 2 ) ^{2} + 1}

\frac{2}{17}

Solution steps

\frac{2}{4 ( - 2 ) ^{2} + 1}

Solve

4 (- 2)^{2} + 1 : 17

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 \cdot 4 + 1

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 16 + 1

Add and subtract (left to right)

16 + 1 : 17

16 + 1

16 + 1 = 17

= 17

= 17

= \frac{2}{17}

\frac{( 7 ^{2} - 33 )}{2 ^{3}}

10 \div 5 + 4 - 16 \div 8 - 2 + 4 \div 4 - 1

4 - 2 (2 - 3 (2 \cdot 3 - 1) - 3) - 1

3 \times 4^{2}

- 5 (1)^{2}