What is (1+1/8)*(2-16/9) ?

The solution to (1+1/8)*(2-16/9) is 1/4

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(1+1/8)*(2-16/9)

(1 + \frac{1}{8}) \cdot (2 - \frac{16}{9})

\frac{1}{4}

Solution steps

(1 + \frac{1}{8}) (2 - \frac{16}{9})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + \frac{1}{8}) : \frac{9}{8}

1 + \frac{1}{8}

1 + \frac{1}{8} = \frac{9}{8}

1 + \frac{1}{8}

Convert element to fraction:

1 = \frac{1 \cdot 8}{8}

= \frac{1 \cdot 8}{8} + \frac{1}{8}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 8 + 1}{8}

1 \cdot 8 + 1 = 9

1 \cdot 8 + 1

Multiply the numbers:

1 \cdot 8 = 8

= 8 + 1

Add the numbers:

8 + 1 = 9

= 9

= \frac{9}{8}

= \frac{9}{8}

= \frac{9}{8} (2 - \frac{16}{9})

Calculate within parentheses

(2 - \frac{16}{9}) : \frac{2}{9}

2 - \frac{16}{9}

2 - \frac{16}{9} = \frac{2}{9}

2 - \frac{16}{9}

Convert element to fraction:

2 = \frac{2 \cdot 9}{9}

= \frac{2 \cdot 9}{9} - \frac{16}{9}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 9 - 16}{9}

2 \cdot 9 - 16 = 2

2 \cdot 9 - 16

Multiply the numbers:

2 \cdot 9 = 18

= 18 - 16

Subtract the numbers:

18 - 16 = 2

= 2

= \frac{2}{9}

= \frac{2}{9}

= \frac{9}{8} \cdot \frac{2}{9}

Multiply and divide (left to right)

\frac{9}{8} \cdot \frac{2}{9} : \frac{1}{4}

\frac{9}{8} \cdot \frac{2}{9}

Cross-cancel common factor:

9

= \frac{2}{8}

Cancel the numbers:

\frac{2}{8} = \frac{1}{4}

= \frac{1}{4}

= \frac{1}{4}

915 + 316 - 518 - 654 + 673 - 185 + 114 + 2396

9 \times 3^{2}

1 2^{2} + 1 0^{2}

6^{2} - 5 (6) - 2

- 3^{2} + 5 (- 3) + 9