What is (-1)^0+(-6)\div (-2)-2^4 ?

The solution to (-1)^0+(-6)\div (-2)-2^4 is -12

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(-1)^0+(-6)\div (-2)-2^4

(- 1)^{0} + (- 6) \div (- 2) - 2^{4}

- 12

Solution steps

(- 1)^{0} + (- 6) \div (- 2) - 2^{4}

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{0} : 1

(- 1)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{0} = 1^{0} = 1

= 1

= 1 + (- 6) \div (- 2) - 2^{4}

Calculate exponents

2^{4} : 16

2^{4}

2^{4} = 16

= 16

= 1 + (- 6) \div (- 2) - 16

Multiply and divide (left to right)

(- 6) \div (- 2) : 3

(- 6) \div (- 2)

Apply rule

(- a) \div (- b) = a \div b

(- 6) \div (- 2) = 6 \div 2 = 3

= 3

= 1 + 3 - 16

Add and subtract (left to right)

1 + 3 - 16 : - 12

1 + 3 - 16

1 + 3 = 4

= 4 - 16

4 - 16 = - 12

= - 12

= - 12

(89 - 12 \times 6) + (1870 \div 2 + 239) - 129

3 + (- 4) - (- 2)

5 + 9 (1) + 2^{2}

(3 + 2)^{3}

8^{2} + 2^{2}

What is (-1)^0+(-6)\div (-2)-2^4 ?
The solution to (-1)^0+(-6)\div (-2)-2^4 is -12