What is (1^2-16)/(1-4) ?

The solution to (1^2-16)/(1-4) is 5

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(1^2-16)/(1-4)

\frac{1 ^{2} - 16}{1 - 4}

5

Solution steps

\frac{1 ^{2} - 16}{1 - 4}

Solve

1^{2} - 16 : - 15

Follow the PEMDAS order of operations

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= 1 - 16

Add and subtract (left to right)

1 - 16 : - 15

1 - 16

1 - 16 = - 15

= - 15

= - 15

Solve

1 - 4 : - 3

1 - 4 = - 3

= - 3

= \frac{- 15}{- 3}

Simplify

\frac{- 15}{- 3} : 5

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{15}{3}

Divide the numbers:

\frac{15}{3} = 5

= 5

= 5

- 3 + 6 - 2 + 4 - 7 + 10

12 - [(6 - 4) + (8 - 15)] - [4 - (3 + 2) - (1 - 7)]

12 \cdot 345 + 12 \cdot 55

315 - \frac{42}{3} + 14 - \frac{36}{12}

(1)^{2} + 5