What is 5(3)+(-7)(-2)^2 ?

The solution to 5(3)+(-7)(-2)^2 is -13

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5(3)+(-7)(-2)^2

5 (3) + (- 7) (- 2)^{2}

- 13

Solution steps

5 (3) + (- 7) (- 2)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 5 (3) + (- 7) \cdot 4

Multiply and divide (left to right)

5 (3) : 15

5 (3)

Apply rule:

(a) = a

(3) = 3

= 5 \cdot 3

Multiply the numbers:

5 \cdot 3 = 15

= 15

= 15 + (- 7) \cdot 4

Multiply and divide (left to right)

(- 7) \cdot 4 : - 28

(- 7) \cdot 4

Apply rule

(- a) \cdot b = - a \cdot b

(- 7) \cdot 4 = - 7 \cdot 4 = - 28

= - 28

= 15 - 28

Add and subtract (left to right)

15 - 28 : - 13

15 - 28

15 - 28 = - 13

= - 13

= - 13

5 (- 1 (7 + 12 - 16) + 4) + 2

(- 12) \times (- 14) \div (- 3)

(5 \cdot 2 \cdot 3)^{4}

2 5^{2} - 2 0^{2}

2 (- 2) - 4