What is (-6\times 1)/((1^2+2)^2) ?

The solution to (-6\times 1)/((1^2+2)^2) is -2/3

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(-6\times 1)/((1^2+2)^2)

\frac{- 6 \cdot 1}{( 1 ^{2} + 2 ) ^{2}}

- \frac{2}{3}

Solution steps

\frac{- 6 \cdot 1}{( 1 ^{2} + 2 ) ^{2}}

Solve

- 6 \cdot 1 : - 6

- 6 \cdot 1 = - 6

= - 6

Solve

(1^{2} + 2)^{2} : 9

Follow the PEMDAS order of operations

Calculate within parentheses

(1^{2} + 2) : 3

1^{2} + 2

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= 1 + 2

Add and subtract (left to right)

1 + 2 : 3

1 + 2

1 + 2 = 3

= 3

= 3

= 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9

= \frac{- 6}{9}

Simplify

\frac{- 6}{9} : - \frac{2}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{6}{9}

Cancel the common factor:

3

= - \frac{2}{3}

= - \frac{2}{3}

1/4 + 5/4 + 6/4

2 (3)^{3} + 16 (3) - 19

- 6 + 9 \times 2

9 \times 8 + 4 \times 2 + 7 \times 2

1 6^{2} \cdot 2

What is (-6\times 1)/((1^2+2)^2) ?
The solution to (-6\times 1)/((1^2+2)^2) is -2/3