What is 3(5-3)^2+7(-2-3)^3 ?

The solution to 3(5-3)^2+7(-2-3)^3 is -863

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3(5-3)^2+7(-2-3)^3

3 (5 - 3)^{2} + 7 (- 2 - 3)^{3}

- 863

Solution steps

3 (5 - 3)^{2} + 7 (- 2 - 3)^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 3) : 2

5 - 3

5 - 3 = 2

= 2

= 3 \cdot 2^{2} + 7 (- 2 - 3)^{3}

Calculate within parentheses

(- 2 - 3) : - 5

- 2 - 3

- 2 - 3 = - 5

= - 5

= 3 \cdot 2^{2} + 7 (- 5)^{3}

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 3 \cdot 4 + 7 (- 5)^{3}

Calculate exponents

(- 5)^{3} : - 125

(- 5)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 5)^{3} = - 5^{3} = - 125

= - 125

= 3 \cdot 4 + 7 (- 125)

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= 12 + 7 (- 125)

Multiply and divide (left to right)

7 (- 125) : - 875

7 (- 125)

Apply rule

a \cdot (- b) = - a \cdot b

7 (- 125) = - 7 \cdot 125 = - 875

= - 875

= 12 - 875

Add and subtract (left to right)

12 - 875 : - 863

12 - 875

12 - 875 = - 863

= - 863

= - 863

1500 - (\frac{1}{3} + \frac{1}{5})

\frac{8}{8 ^{2} + 1}

(2 \times 3) - (10 \div 5 - 7)

6 (7) - 6 (4)

1 + 1 \div 25