What is (-7-2)^3\div (-9)+6^2 ?

The solution to (-7-2)^3\div (-9)+6^2 is 117

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(-7-2)^3\div (-9)+6^2

(- 7 - 2)^{3} \div (- 9) + 6^{2}

117

Solution steps

(- 7 - 2)^{3} \div (- 9) + 6^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(- 7 - 2) : - 9

- 7 - 2

- 7 - 2 = - 9

= - 9

= (- 9)^{3} \div (- 9) + 6^{2}

Calculate exponents

(- 9)^{3} : - 729

(- 9)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 9)^{3} = - 9^{3} = - 729

= - 729

= - 729 \div (- 9) + 6^{2}

Calculate exponents

6^{2} : 36

6^{2}

6^{2} = 36

= 36

= - 729 \div (- 9) + 36

Multiply and divide (left to right)

- 729 \div (- 9) : 81

- 729 \div (- 9)

Apply rule

- a \div (- b) = a \div b

- 729 \div (- 9) = 729 \div 9 = 81

= 81

= 81 + 36

Add and subtract (left to right)

81 + 36 : 117

81 + 36

81 + 36 = 117

= 117

= 117

[4 - (8 \div 4^{2})] 3 + 3

24 \div 4 \times 6

9 - 9 \cdot 10

- 4^{2} + 16

- 4^{2} + 21