What is 3+4\times (6-3\times 2) ?

The solution to 3+4\times (6-3\times 2) is 3

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3+4\times (6-3\times 2)

3 + 4 \cdot (6 - 3 \cdot 2)

3

Solution steps

3 + 4 (6 - 3 \cdot 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(6 - 3 \cdot 2) : 0

6 - 3 \cdot 2

Multiply and divide (left to right)

3 \cdot 2 : 6

3 \cdot 2

3 \cdot 2 = 6

= 6

= 6 - 6

Add and subtract (left to right)

6 - 6 : 0

6 - 6

6 - 6 = 0

= 0

= 0

= 3 + 4 \cdot 0

Multiply and divide (left to right)

4 \cdot 0 : 0

4 \cdot 0

4 \cdot 0 = 0

= 0

= 3 + 0

Add and subtract (left to right)

3 + 0 : 3

3 + 0

3 + 0 = 3

= 3

= 3

- 7^{2} + 18 (7)

- \frac{2}{3} (6) + 1

- 7 \times (- 254) - (27 + 7) - 3

- 1 (- 4) - 8 (- 4) + 12

\frac{50000}{3 ( 1 ) + 10}