What is (1)^2+2(1)-1 ?

The solution to (1)^2+2(1)-1 is 2

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(1)^2+2(1)-1

(1)^{2} + 2 (1) - 1

2

Solution steps

(1)^{2} + 2 (1) - 1

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 1 + 2 (1) - 1

Multiply and divide (left to right)

2 (1) : 2

2 (1)

Apply rule:

(a) = a

(1) = 1

= 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2

= 1 + 2 - 1

Add and subtract (left to right)

1 + 2 - 1 : 2

1 + 2 - 1

1 + 2 = 3

= 3 - 1

3 - 1 = 2

= 2

= 2

- 5 \times (- 3 \times \frac{4}{2}) \div (- 3) + 1

(- 3 + 7) \cdot (- 2)

\frac{- 28 + 4 ( 3 )}{2}

(- 4)^{2} - 3 (- 4) - 4

36 \cdot \frac{3}{5} + 22 \cdot \frac{4}{5}