What is 10-(+20)\div [7+(-3)] ?

The solution to 10-(+20)\div [7+(-3)] is 5

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10-(+20)\div [7+(-3)]

10 - (+ 20) \div [7 + (- 3)]

5

Solution steps

10 - (20) \div [7 + (- 3)]

Follow the PEMDAS order of operations

Calculate within parentheses

[7 + (- 3)] : 4

7 + (- 3)

Add and subtract (left to right)

Apply rule

+ (- a) = - a

+ (- 3) = - 3

= 7 - 3

7 - 3 = 4

= 4

= 10 - (20) \div 4

Multiply and divide (left to right)

(20) \div 4 : \frac{( 20 )}{4}

(20) \div 4

(20) \div 4 = \frac{( 20 )}{4}

= \frac{( 20 )}{4}

= 10 - \frac{( 20 )}{4}

Add and subtract (left to right)

10 - \frac{( 20 )}{4} : 5

10 - \frac{( 20 )}{4}

10 - \frac{( 20 )}{4} = 5

10 - \frac{20}{4}

Divide the numbers:

\frac{20}{4} = 5

= 10 - 5

Subtract the numbers:

10 - 5 = 5

= 5

= 5

= 5

(- 1)^{2} + 5 (- 1) + 2

7 (- 5) (- 2) (- 1) + 72

(3^{5} - 1 5^{2}) \div (2^{0} + 2^{1})

- 4 + 1 - 4

\frac{2}{3} - 1 - \frac{1}{6}