What is (6+3)^2-(4-8)^2+3\div 1/3 ?

The solution to (6+3)^2-(4-8)^2+3\div 1/3 is 74

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(6+3)^2-(4-8)^2+3\div 1/3

(6 + 3)^{2} - (4 - 8)^{2} + 3 \div \frac{1}{3}

74

Solution steps

(6 + 3)^{2} - (4 - 8)^{2} + 3 \div \frac{1}{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(6 + 3) : 9

6 + 3

6 + 3 = 9

= 9

= 9^{2} - (4 - 8)^{2} + 3 \div \frac{1}{3}

Calculate within parentheses

(4 - 8) : - 4

4 - 8

4 - 8 = - 4

= - 4

= 9^{2} - (- 4)^{2} + 3 \div \frac{1}{3}

Calculate exponents

9^{2} : 81

9^{2}

9^{2} = 81

= 81

= 81 - (- 4)^{2} + 3 \div \frac{1}{3}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 81 - 16 + 3 \div \frac{1}{3}

Multiply and divide (left to right)

3 \div \frac{1}{3} : 9

3 \div \frac{1}{3}

Convert element to fraction:

3 = \frac{3}{1}

= \frac{3}{1} \div \frac{1}{3}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{3}{1} \cdot \frac{3}{1}

Apply rule

\frac{a}{1} = a

= 3 \cdot 3

Multiply the numbers:

3 \cdot 3 = 9

= 9

= 81 - 16 + 9

Add and subtract (left to right)

81 - 16 + 9 : 74

81 - 16 + 9

81 - 16 = 65

= 65 + 9

65 + 9 = 74

= 74

= 74

- 2 \cdot \frac{2}{5} + 3

(4) \times (- 20) - (- 120) \div (2) + 28 \div (- 7)

5/4 + 3/7 + 8/9

- 1^{2} + 3 (- 1) - 1

[(10 \times 3)] \div 5

What is (6+3)^2-(4-8)^2+3\div 1/3 ?
The solution to (6+3)^2-(4-8)^2+3\div 1/3 is 74