What is (3)^2+2(3)+3 ?

The solution to (3)^2+2(3)+3 is 18

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(3)^2+2(3)+3

(3)^{2} + 2 (3) + 3

18

Solution steps

(3)^{2} + 2 (3) + 3

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 9 + 2 (3) + 3

Multiply and divide (left to right)

2 (3) : 6

2 (3)

Apply rule:

(a) = a

(3) = 3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= 9 + 6 + 3

Add and subtract (left to right)

9 + 6 + 3 : 18

9 + 6 + 3

9 + 6 = 15

= 15 + 3

15 + 3 = 18

= 18

= 18

(- 1)^{2} - 2 (- 1) + 3

(- 1)^{2} - 2 (- 1) - 1

(- 1)^{2} - 2 (- 1) - 2

6 (4) - 8

12 (4 - (- 2 (5 - 1 - 9)) - 1 + 2) \times 3