What is 3*(-10)^2-6*(-10) ?

The solution to 3*(-10)^2-6*(-10) is 360

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3(-10)^2-6(-10)

3 \cdot (- 10)^{2} - 6 \cdot (- 10)

360

Solution steps

3 (- 10)^{2} - 6 (- 10)

Follow the PEMDAS order of operations

Calculate exponents

(- 10)^{2} : 100

(- 10)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 10)^{2} = 1 0^{2} = 100

= 100

= 3 \cdot 100 - 6 (- 10)

Multiply and divide (left to right)

3 \cdot 100 : 300

3 \cdot 100

3 \cdot 100 = 300

= 300

= 300 - 6 (- 10)

Multiply and divide (left to right)

6 (- 10) : - 60

6 (- 10)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 10) = - 6 \cdot 10 = - 60

= - 60

= 300 - (- 60)

Add and subtract (left to right)

300 - (- 60) : 360

300 - (- 60)

Apply rule

- (- a) = + a

- (- 60) = + 60

= 300 + 60

300 + 60 = 360

= 360

= 360

2^{2} \times 3^{2} \times 7

(2 - 6) + 3 (- 6) + 4 (8 - 6)

(2^{2} 7^{2})^{2}

\frac{3 - 3 ( - 1 )}{6}

\frac{( - 7 ) ^{8}}{( - 7 ) ^{5}}