What is (-2)^4\div 2^3-4^2\div (-2)^2 ?

The solution to (-2)^4\div 2^3-4^2\div (-2)^2 is -2

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(-2)^4\div 2^3-4^2\div (-2)^2

(- 2)^{4} \div 2^{3} - 4^{2} \div (- 2)^{2}

- 2

Solution steps

(- 2)^{4} \div 2^{3} - 4^{2} \div (- 2)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{4} : 16

(- 2)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

= 16 \div 2^{3} - 4^{2} \div (- 2)^{2}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 16 \div 8 - 4^{2} \div (- 2)^{2}

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 \div 8 - 16 \div (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 16 \div 8 - 16 \div 4

Multiply and divide (left to right)

16 \div 8 : 2

16 \div 8

16 \div 8 = 2

= 2

= 2 - 16 \div 4

Multiply and divide (left to right)

16 \div 4 : 4

16 \div 4

16 \div 4 = 4

= 4

= 2 - 4

Add and subtract (left to right)

2 - 4 : - 2

2 - 4

2 - 4 = - 2

= - 2

= - 2

3 (6)^{0}

- 64 \div 16 - 45 - 7 (- 8)

16 \div 4^{2}

\frac{9}{5} (10) + 32

4 \div 7 \times 9 \div 9

What is (-2)^4\div 2^3-4^2\div (-2)^2 ?
The solution to (-2)^4\div 2^3-4^2\div (-2)^2 is -2