What is (2+4)\times (4+(-1/3)) ?

The solution to (2+4)\times (4+(-1/3)) is 22

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(2+4)\times (4+(-1/3))

(2 + 4) \cdot (4 + (- \frac{1}{3}))

22

Solution steps

(2 + 4) (4 + (- \frac{1}{3}))

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 4) : 6

2 + 4

2 + 4 = 6

= 6

= 6 (4 + (- \frac{1}{3}))

Calculate within parentheses

(4 + (- \frac{1}{3})) : \frac{11}{3}

4 + (- \frac{1}{3})

Add and subtract (left to right)

Apply rule

+ (- a) = - a

+ (- \frac{1}{3}) = - \frac{1}{3}

= 4 - \frac{1}{3}

4 - \frac{1}{3} = \frac{11}{3}

4 - \frac{1}{3}

Convert element to fraction:

4 = \frac{4 \cdot 3}{3}

= \frac{4 \cdot 3}{3} - \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 3 - 1}{3}

4 \cdot 3 - 1 = 11

4 \cdot 3 - 1

Multiply the numbers:

4 \cdot 3 = 12

= 12 - 1

Subtract the numbers:

12 - 1 = 11

= 11

= \frac{11}{3}

= \frac{11}{3}

= 6 \cdot \frac{11}{3}

Multiply and divide (left to right)

6 \cdot \frac{11}{3} : 22

6 \cdot \frac{11}{3}

Convert element to fraction:

6 = \frac{6}{1}

= \frac{6}{1} \cdot \frac{11}{3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{6 \cdot 11}{1 \cdot 3}

Cancel

\frac{6 \cdot 11}{1 \cdot 3} : 22

\frac{6 \cdot 11}{1 \cdot 3}

Multiply the numbers:

1 \cdot 3 = 3

= \frac{6 \cdot 11}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2 \cdot 11

Multiply the numbers:

2 \cdot 11 = 22

= 22

= 22

= 22

(- 1)^{2} - 3 \times (- 1) + 2

3 - 2 \cdot 1 - 10 \cdot (- 3)

1 1^{2} - 3^{2}

7 + 2 \times 3

25 + 12 + (8 - 5) + 5 + 2