What is 8(1)^2-7(1)+8 ?

The solution to 8(1)^2-7(1)+8 is 9

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8(1)^2-7(1)+8

8 (1)^{2} - 7 (1) + 8

9

Solution steps

8 (1)^{2} - 7 (1) + 8

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 8 \cdot 1 - 7 (1) + 8

Multiply and divide (left to right)

8 \cdot 1 : 8

8 \cdot 1

8 \cdot 1 = 8

= 8

= 8 - 7 (1) + 8

Multiply and divide (left to right)

7 (1) : 7

7 (1)

Apply rule:

(a) = a

(1) = 1

= 7 \cdot 1

Multiply the numbers:

7 \cdot 1 = 7

= 7

= 8 - 7 + 8

Add and subtract (left to right)

8 - 7 + 8 : 9

8 - 7 + 8

8 - 7 = 1

= 1 + 8

1 + 8 = 9

= 9

= 9

2 (5) + (4^{2} + (- 32)) \div 4

- 4 (- 11 \times 2 - 14)

(- 10) + 35 + 176

\frac{1}{2} (4) + 18

\frac{1}{6} + \frac{1}{7}