The solution to -2/5 (2)-2 is -14/5

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-2/5 (2)-2

Solution

- \frac{2}{5} (2) - 2

- \frac{14}{5}

Solution steps

- \frac{2}{5} (2) - 2

Follow the PEMDAS order of operations

Multiply and divide (left to right)

- \frac{2}{5} (2) : - \frac{4}{5}

- \frac{2}{5} (2)

Apply rule:

(a) = a

(2) = 2

= - \frac{2}{5} \cdot 2

- \frac{2}{5} \cdot 2 = - \frac{4}{5}

- \frac{2}{5} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= - \frac{2}{5} \cdot \frac{2}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{2}{5} \cdot \frac{2}{1} = \frac{2 \cdot 2}{5 \cdot 1}

= - \frac{2 \cdot 2}{5 \cdot 1}

Multiply the numbers:

2 \cdot 2 = 4

= - \frac{4}{5 \cdot 1}

Multiply the numbers:

5 \cdot 1 = 5

= - \frac{4}{5}

= - \frac{4}{5}

= - \frac{4}{5} - 2

Add and subtract (left to right)

- \frac{4}{5} - 2 : - \frac{14}{5}

- \frac{4}{5} - 2

- \frac{4}{5} - 2 = - \frac{14}{5}

- \frac{4}{5} - 2

Convert element to fraction:

2 = \frac{2 \cdot 5}{5}

= - \frac{2 \cdot 5}{5} - \frac{4}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 \cdot 5 - 4}{5}

- 2 \cdot 5 - 4 = - 14

- 2 \cdot 5 - 4

Multiply the numbers:

2 \cdot 5 = 10

= - 10 - 4

Subtract the numbers:

- 10 - 4 = - 14

= - 14

= \frac{- 14}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{14}{5}

= - \frac{14}{5}

= - \frac{14}{5}

48 + [15 - (43 - 38) - 27]

8 \times 5 - 7 - 4 + 3 \times 2

(1 - 0)^{2}

- 36 - 35 - 34

2^{5} + 2^{2}