What is (252^2-23^2)/(275) ?

The solution to (252^2-23^2)/(275) is 229

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(252^2-23^2)/(275)

\frac{25 2 ^{2} - 2 3 ^{2}}{275}

229

Solution steps

\frac{25 2 ^{2} - 2 3 ^{2}}{275}

Solve

25 2^{2} - 2 3^{2} : 62975

Follow the PEMDAS order of operations

Calculate exponents

25 2^{2} : 63504

25 2^{2}

25 2^{2} = 63504

= 63504

= 63504 - 2 3^{2}

Calculate exponents

2 3^{2} : 529

2 3^{2}

2 3^{2} = 529

= 529

= 63504 - 529

Add and subtract (left to right)

63504 - 529 : 62975

63504 - 529

63504 - 529 = 62975

= 62975

= 62975

= \frac{62975}{275}

Divide the numbers:

\frac{62975}{275} = 229

= 229

(13 \cdot 14)^{3}

5 (- 1) + 5

(37 - 19) - (51 - 103 - 17) + (- 3 + 6)

- \frac{1}{5} (360) + 144

4 \times 8 \times 2 \div 4