The solution to 1-7/3-2/3 is -2

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1-7/3-2/3

Solution

1 - \frac{7}{3} - \frac{2}{3}

- 2

Solution steps

1 - \frac{7}{3} - \frac{2}{3}

Follow the PEMDAS order of operations

Add and subtract (left to right)

1 - \frac{7}{3} = - \frac{4}{3}

1 - \frac{7}{3}

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= \frac{1 \cdot 3}{3} - \frac{7}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 3 - 7}{3}

1 \cdot 3 - 7 = - 4

1 \cdot 3 - 7

Multiply the numbers:

1 \cdot 3 = 3

= 3 - 7

Subtract the numbers:

3 - 7 = - 4

= - 4

= \frac{- 4}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{3}

= - \frac{4}{3} - \frac{2}{3}

- \frac{4}{3} - \frac{2}{3} = - 2

- \frac{4}{3} - \frac{2}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 4 - 2}{3}

Subtract the numbers:

- 4 - 2 = - 6

= \frac{- 6}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{6}{3}

Divide the numbers:

\frac{6}{3} = 2

= - 2

= - 2

- 4 (14) - 3

1/3 (5)^{2} (5 + 1)

6 (2) - 3 (2)^{2}

5 - (- \frac{1}{9}) - \frac{17}{2}

2 - \frac{1}{3} + 1 + \frac{2}{3}