What is 10*[3-2*(5-6)-2*(4-8)] ?

The solution to 10*[3-2*(5-6)-2*(4-8)] is 130

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10[3-2(5-6)-2*(4-8)]

10 \cdot [3 - 2 \cdot (5 - 6) - 2 \cdot (4 - 8)]

130

Solution steps

10 [3 - 2 (5 - 6) - 2 (4 - 8)]

Follow the PEMDAS order of operations

Calculate within parentheses

[3 - 2 \cdot (5 - 6) - 2 \cdot (4 - 8)] : 13

3 - 2 (5 - 6) - 2 (4 - 8)

Calculate within parentheses

(5 - 6) : - 1

5 - 6

5 - 6 = - 1

= - 1

= 3 - 2 (- 1) - 2 (4 - 8)

Calculate within parentheses

(4 - 8) : - 4

4 - 8

4 - 8 = - 4

= - 4

= 3 - 2 (- 1) - 2 (- 4)

Multiply and divide (left to right)

2 (- 1) : - 2

2 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 1) = - 2 \cdot 1 = - 2

= - 2

= 3 - (- 2) - 2 (- 4)

Multiply and divide (left to right)

2 (- 4) : - 8

2 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 4) = - 2 \cdot 4 = - 8

= - 8

= 3 - (- 2) - (- 8)

Add and subtract (left to right)

3 - (- 2) - (- 8) : 13

3 - (- 2) - (- 8)

Apply rule

- (- a) = + a

- (- 2) = + 2

= 3 + 2 - (- 8)

3 + 2 = 5

= 5 - (- 8)

Apply rule

- (- a) = + a

- (- 8) = + 8

= 5 + 8

5 + 8 = 13

= 13

= 13

= 10 \cdot 13

Multiply and divide (left to right)

10 \cdot 13 : 130

10 \cdot 13

10 \cdot 13 = 130

= 130

= 130

1 0^{2} + 2 4^{2}

2 + 2 \cdot 2 - 2

2^{3} - 4 + \frac{20}{4}

\frac{75}{100}

- 2^{2} + 4