What is -3(4+3)\div 6\times (-2) ?

The solution to -3(4+3)\div 6\times (-2) is 7

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-3(4+3)\div 6\times (-2)

- 3 (4 + 3) \div 6 \times (- 2)

7

Solution steps

- 3 (4 + 3) \div 6 \times (- 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(4 + 3) : 7

4 + 3

4 + 3 = 7

= 7

= - 3 \cdot 7 \div 6 \times (- 2)

Multiply and divide (left to right)

- 3 \cdot 7 \div 6 \times (- 2) : 7

- 3 \cdot 7 \div 6 \times (- 2)

- 3 \cdot 7 = - 21

= - 21 \div 6 \times (- 2)

- 21 \div 6 = \frac{- 21}{6}

= \frac{- 21}{6} \times (- 2)

\frac{- 21}{6} \times (- 2) = 7

\frac{- 21}{6} \times (- 2)

Apply rule

a \times (- b) = - a \times b

\frac{- 21}{6} \times (- 2) = - \frac{- 21}{6} \times 2

Cancel

\frac{- 21}{6} : - \frac{7}{2}

\frac{- 21}{6}

Factor the number:

21 = 3 \cdot 7

= \frac{- 3 \cdot 7}{6}

Factor the number:

6 = 3 \cdot 2

= \frac{- 3 \cdot 7}{3 \cdot 2}

Cancel the common factor:

3

= \frac{- 7}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{7}{2}

= - (- \frac{7}{2}) \cdot 2

Apply rule:

- (- a) = a

- (- \frac{7}{2}) = \frac{7}{2}

= \frac{7}{2} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= \frac{7}{2} \cdot \frac{2}{1}

Cross-cancel common factor:

2

= \frac{7}{1}

Divide the numbers:

\frac{7}{1} = 7

= 7

= 7

= 7

- 3 (- 2^{2}) + 10

3 + 8 [9 - (8 - 2)]

\frac{3 ( 4 + 2 )}{1 + 4 ^{2} - 14}

32 - 19 + 40 - 20 + 30 - 50

- 6 (0) + 5

What is -3(4+3)\div 6\times (-2) ?
The solution to -3(4+3)\div 6\times (-2) is 7