What is -2(3)^2+7(3)+5 ?

The solution to -2(3)^2+7(3)+5 is 8

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-2(3)^2+7(3)+5

- 2 (3)^{2} + 7 (3) + 5

8

Solution steps

- 2 (3)^{2} + 7 (3) + 5

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= - 2 \cdot 9 + 7 (3) + 5

Multiply and divide (left to right)

- 2 \cdot 9 : - 18

- 2 \cdot 9

- 2 \cdot 9 = - 18

= - 18

= - 18 + 7 (3) + 5

Multiply and divide (left to right)

7 (3) : 21

7 (3)

Apply rule:

(a) = a

(3) = 3

= 7 \cdot 3

Multiply the numbers:

7 \cdot 3 = 21

= 21

= - 18 + 21 + 5

Add and subtract (left to right)

- 18 + 21 + 5 : 8

- 18 + 21 + 5

- 18 + 21 = 3

= 3 + 5

3 + 5 = 8

= 8

= 8

[(+ 5) - (+ 2)] \div [(- 8) + (- 3) - (- 10)]

4 (8) + 1

2^{2} + 50 \times 35 - (10 + 6 \times 5)

(3 + 1)^{2} + 2 \times 5 - 1 0^{0}

4 + (- 1 (- 2 - 1))^{2}