What is ((-2)^4)/((3^2+2^2)^2) ?

The solution to ((-2)^4)/((3^2+2^2)^2) is 16/169

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((-2)^4)/((3^2+2^2)^2)

\frac{( - 2 ) ^{4}}{( 3 ^{2} + 2 ^{2} ) ^{2}}

\frac{16}{169}

Solution steps

\frac{( - 2 ) ^{4}}{( 3 ^{2} + 2 ^{2} ) ^{2}}

Solve

(- 2)^{4} : 16

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

Solve

(3^{2} + 2^{2})^{2} : 169

Follow the PEMDAS order of operations

Calculate within parentheses

(3^{2} + 2^{2}) : 13

3^{2} + 2^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 + 2^{2}

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 9 + 4

Add and subtract (left to right)

9 + 4 : 13

9 + 4

9 + 4 = 13

= 13

= 13

= 1 3^{2}

Calculate exponents

1 3^{2} : 169

1 3^{2}

1 3^{2} = 169

= 169

= 169

= \frac{16}{169}

2^{2} \times [3^{2} - (4 + 8)] + 4 \div 2

\frac{9}{5} \times 10 + 32

3^{2} - 2 \times 3

4 (- 2) + (- 10) + 3 (- 8)

- 2 - 3 \times 2

What is ((-2)^4)/((3^2+2^2)^2) ?
The solution to ((-2)^4)/((3^2+2^2)^2) is 16/169