What is -2*(-1)^2+4*(-1) ?

The solution to -2*(-1)^2+4*(-1) is -6

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-2(-1)^2+4(-1)

- 2 \cdot (- 1)^{2} + 4 \cdot (- 1)

- 6

Solution steps

- 2 (- 1)^{2} + 4 (- 1)

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 2 \cdot 1 + 4 (- 1)

Multiply and divide (left to right)

- 2 \cdot 1 : - 2

- 2 \cdot 1

- 2 \cdot 1 = - 2

= - 2

= - 2 + 4 (- 1)

Multiply and divide (left to right)

4 (- 1) : - 4

4 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 1) = - 4 \cdot 1 = - 4

= - 4

= - 2 - 4

Add and subtract (left to right)

- 2 - 4 : - 6

- 2 - 4

- 2 - 4 = - 6

= - 6

= - 6

0 - 2 (\frac{1}{5})

(- 2) \cdot (- 2) \cdot (- 2)

\frac{3}{4} (- 12) + 10

- 2 (- 2 + 2)

- 6 + 9 - 3 - 5 + 7 - 8 + 9