What is (4)^2-4(4)+6 ?

The solution to (4)^2-4(4)+6 is 6

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(4)^2-4(4)+6

(4)^{2} - 4 (4) + 6

6

Solution steps

(4)^{2} - 4 (4) + 6

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 16 - 4 (4) + 6

Multiply and divide (left to right)

4 (4) : 16

4 (4)

Apply rule:

(a) = a

(4) = 4

= 4 \cdot 4

Multiply the numbers:

4 \cdot 4 = 16

= 16

= 16 - 16 + 6

Add and subtract (left to right)

16 - 16 + 6 : 6

16 - 16 + 6

16 - 16 = 0

= 0 + 6

0 + 6 = 6

= 6

= 6

\frac{\frac{7}{3}}{23}

\frac{( - 4 ) ^{2}}{( - 4 ) ^{7}}

- 3 \times 1 - 2

- 3 \times 1 + 6

- 1 (0) + 0