What is 3^2-4(3)(-2)+2(1) ?

The solution to 3^2-4(3)(-2)+2(1) is 35

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3^2-4(3)(-2)+2(1)

3^{2} - 4 (3) (- 2) + 2 (1)

35

Solution steps

3^{2} - 4 (3) (- 2) + 2 (1)

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 - 4 (3) (- 2) + 2 (1)

Multiply and divide (left to right)

4 (3) (- 2) : - 24

4 (3) (- 2)

4 (3) = 12

4 (3)

Apply rule:

(a) = a

(3) = 3

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= 12 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

12 (- 2) = - 12 \cdot 2 = - 24

= - 24

= 9 - (- 24) + 2 (1)

Multiply and divide (left to right)

2 (1) : 2

2 (1)

Apply rule:

(a) = a

(1) = 1

= 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2

= 9 - (- 24) + 2

Add and subtract (left to right)

9 - (- 24) + 2 : 35

9 - (- 24) + 2

Apply rule

- (- a) = + a

- (- 24) = + 24

= 9 + 24 + 2

9 + 24 = 33

= 33 + 2

33 + 2 = 35

= 35

= 35

7 \times 8^{0}

20 - 5 ((- 2) (4 - 7) + 8 - 25)

1 0^{12} - 1 0^{11}

2 \times (- 10) + 30

\frac{4 \cdot 500 + 10 \cdot 200}{700}