What is (-2)/(-2^2-3) ?

The solution to (-2)/(-2^2-3) is 2/7

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(-2)/(-2^2-3)

\frac{- 2}{- 2 ^{2} - 3}

\frac{2}{7}

Solution steps

\frac{- 2}{- 2 ^{2} - 3}

Solve

- 2^{2} - 3 : - 7

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= - 4 - 3

Add and subtract (left to right)

- 4 - 3 : - 7

- 4 - 3

- 4 - 3 = - 7

= - 7

= - 7

= \frac{- 2}{- 7}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2}{7}

[(- 4 + 2) - 6] + (8 + 4) - (- 2 - 5) \cdot (4 - 6)

- 2 \cdot (- 1) + 3

(6 + 4) \times 3

8 (12 + 8)

\frac{1 \cdot ( 13 ) ^{3}}{12}