What is 1+2[(-2)^3-(-3)^2] ?

The solution to 1+2[(-2)^3-(-3)^2] is -33

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1+2[(-2)^3-(-3)^2]

1 + 2 [(- 2)^{3} - (- 3)^{2}]

- 33

Solution steps

1 + 2 [(- 2)^{3} - (- 3)^{2}]

Follow the PEMDAS order of operations

Calculate within parentheses

[(- 2)^{3} - (- 3)^{2}] : - 17

(- 2)^{3} - (- 3)^{2}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 - (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 8 - 9

Add and subtract (left to right)

- 8 - 9 : - 17

- 8 - 9

- 8 - 9 = - 17

= - 17

= - 17

= 1 + 2 (- 17)

Multiply and divide (left to right)

2 (- 17) : - 34

2 (- 17)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 17) = - 2 \cdot 17 = - 34

= - 34

= 1 - 34

Add and subtract (left to right)

1 - 34 : - 33

1 - 34

1 - 34 = - 33

= - 33

= - 33

- 4 (5) + 2

- (4)^{2} + 6 (4) - 8

4 - 2 (9 - 6) 3 \div 6 \times 2 + (6 \div 3 \times 5 - 7) 2

- 1 + 4 (- 3) \div 2

6 (1 + 1) - 2 (3 + 4) - 2