The solution to -1/3+2-3 is -4/3

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-1/3+2-3

Solution

- \frac{1}{3} + 2 - 3

- \frac{4}{3}

Solution steps

- \frac{1}{3} + 2 - 3

Follow the PEMDAS order of operations

Add and subtract (left to right)

- \frac{1}{3} + 2 = \frac{5}{3}

- \frac{1}{3} + 2

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} - \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 - 1}{3}

2 \cdot 3 - 1 = 5

2 \cdot 3 - 1

Multiply the numbers:

2 \cdot 3 = 6

= 6 - 1

Subtract the numbers:

6 - 1 = 5

= 5

= \frac{5}{3}

= \frac{5}{3} - 3

\frac{5}{3} - 3 = - \frac{4}{3}

\frac{5}{3} - 3

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= - \frac{3 \cdot 3}{3} + \frac{5}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 3 + 5}{3}

- 3 \cdot 3 + 5 = - 4

- 3 \cdot 3 + 5

Multiply the numbers:

3 \cdot 3 = 9

= - 9 + 5

Add/Subtract the numbers:

- 9 + 5 = - 4

= - 4

= \frac{- 4}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{3}

= - \frac{4}{3}

3 6^{2} - 4 \times 16 \times 20

96 \div (12 \times 4) \div 2

[2 - [2 (5 - 3) + 8]]

- 2 {+ 5 (2 + 3) + 6 (- 1 - 3)}

50 - 94 + 6