What is (2\div 3)+(1\div 3) ?

The solution to (2\div 3)+(1\div 3) is 1

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(2\div 3)+(1\div 3)

(2 \div 3) + (1 \div 3)

1

Solution steps

(2 \div 3) + (1 \div 3)

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \div 3) : \frac{2}{3}

2 \div 3

2 \div 3 = \frac{2}{3}

= \frac{2}{3}

= \frac{2}{3} + (1 \div 3)

Calculate within parentheses

(1 \div 3) : \frac{1}{3}

1 \div 3

1 \div 3 = \frac{1}{3}

= \frac{1}{3}

= \frac{2}{3} + \frac{1}{3}

Add and subtract (left to right)

\frac{2}{3} + \frac{1}{3} : 1

\frac{2}{3} + \frac{1}{3}

\frac{2}{3} + \frac{1}{3} = 1

\frac{2}{3} + \frac{1}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 1

= 1

\frac{- 8 ^{2} + 3 ( - 8 )}{4 ( - 8 ) + 27}

2280 - 1500 - 850 - 680

4^{3} \div ((28 - 3^{3}) + 121 \div 1 1^{2})^{3}

\frac{3 ^{5}}{1 + 2 ^{5}}

- 2 (1)^{2} + 8 (1) - 5